-3s^2-30s-50=0

Solution for -3s^2-30s-50=0 equation:

-3s^2-30s-50=0

a = -3; b = -30; c = -50;
Δ = b2-4ac
Δ = -302-4·(-3)·(-50)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{3}}{2*-3}=\frac{30-10\sqrt{3}}{-6}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{3}}{2*-3}=\frac{30+10\sqrt{3}}{-6}
$